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Exercise 2 — Cartesian Products

Difficulty: Easy Status: Complete

Give the geometric interpretation of the following Cartesian products:

(a) two line segments; (b) two lines; (c) a line and a circle; (d) a line and a disk; (e) two circles; (f) a circle and a disk.

Let I=[0,1]I = [0,1], R\mathbb{R} be the real line, S1={(x,y)∈R2:x2+y2=1}S^1 = \{ (x,y) \in \mathbb{R}^2 : x^2 + y^2 = 1 \} be the unit circle, and D2={(x,y)∈R2:x2+y2≤1}D^2 = \{ (x,y) \in \mathbb{R}^2 : x^2 + y^2 \le 1 \} be the closed unit disk.

ProductNotationGeometric interpretation
(a) I×II \times ITwo segmentsRectangle (including interior)
(b) R×R\mathbb{R} \times \mathbb{R}Two linesPlane R2\mathbb{R}^2
(c) R×S1\mathbb{R} \times S^1Line ×\times circleInfinite cylinder (without caps)
(d) R×D2\mathbb{R} \times D^2Line ×\times diskSolid infinite cylinder
(e) S1×S1S^1 \times S^1Circle ×\times circleTorus (surface of a doughnut)
(f) S1×D2S^1 \times D^2Circle ×\times diskSolid torus (filled doughnut)

The general principle: the Cartesian product X×YX \times Y of two sets that are “geometric objects” of dimensions pp and qq respectively yields an object of dimension p+qp + q — provided one interprets “dimension” appropriately.

  • (a) 1+1=21 + 1 = 2 (rectangle)
  • (c) 1+1=21 + 1 = 2 (cylinder surface, a 2-manifold)
  • (d) 1+2=31 + 2 = 3 (solid cylinder)
  • (e) 1+1=21 + 1 = 2 (torus surface)
  • (f) 1+2=31 + 2 = 3 (solid torus)
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